Tutorial 119 |
Multiplying two selected 3-digit numbers (middle digit 1)
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- Select a 3-digit number with a middle digit of 1.
- Choose a multiplier with the same first two digits, whose third digit sums to
10 with the third digit of the first 3-digit number.
- The last two digits will be the product of the first digits:
_ _ _ 0 X or _ _ _ _ X X.
- The third digit from the right will be 2:
_ _ 2 _ _ or _ _ _ 2 _ _ .
- The next digit to the left will be 3 times the first digit of the number (keep
carry):
_ X _ _ _ or _ _ X _ _ _.
- The first digits will be the square of the first digit plus the carry:
X _ _ _ _ or X X _ _ _ _.
As you determine the digits in the answer from right to left, repeat them to yourself
at each step until you have the whole answer.
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Example:
- If the first number is 814, choose 816 as the second number (same
first digits, second digits add to 10).
- 4 × 6 = 24 (multiply the first digits) - last two digits:
_ _ _ _ 2 4.
- The third digit from the right is 2: _ _ 2 _ _ .
- 8 × 3 = 24 (the next digit to the left is 3 times the first digit (keep carry 2): _ _ 4 _ _ _ .
- 8 × 8 = 64; 64 + 2 = 66 ( the first digits are the square of the first digit
plus the carry: 6 6 _ _ _ _.
- So 814 × 816 = 664224.
See the pattern?
- If the first number is 317, choose 313 as the multiplier (same
first digits, second digits add to 10).
- 7 × 3 = 21 (multiply the first digits) - last two digits:
_ _ _ _ 2 1.
- The third digit from the right is 2: _ _ 2 _ _ .
- 3 × 3 = 9 (the next digit to the left is 3 times the first digit (no carry): _ 9 _ _ _ .
- 3 × 3 = 9 ( the first digits are the square of the first digit: 9 _ _ _ _.
- So 317 × 313 = 99221.
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