Squaring special numbers (9's and final 1)
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- Choose a number with repeating 9's and a final 1.
- The square is made up of:
- one fewer 9 than there are repeating 9's
- 82
- the same number of 0's as there are 9's in the square
- A final 81
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Example:
- If the number to be squared is 9991:
- The square has:
One fewer 9 than the
repeating 9's: 9 9
82
8 2
same number of 0's as 9's
in the square 0
0
a final 81
8 1
So 9991 × 9991 = 99820081.
See the pattern?
- If the number to be squared is 999991:
- The square has:
one fewer 9 than the
repeating 9's: 9 9 9 9
82
8 2
same number of 0's as 9's
in the square 0
0 0 0
a final 81
8 1
- So 999991 × 999991 = 999982000081.
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