Squaring special numbers (9's and final 3)
|
|
- Choose a number with repeating 9's and a final 3.
- The square is made up of:
- one fewer 9 than there are repeating 9's
- 86
- the same number of 0's as there are 9's in the square
- A final 49
|
Example:
- If the number to be squared is 9993:
- The square has:
one fewer 9 than the
repeating 9's: 9
9
86
8 6
same number of 0's as 9's
in the square
0 0
a final 49
4 9
- So 9993 × 9993 = 99860049.
See the pattern?
- If the number to be squared is 999993:
- The square has:
one fewer 9 than the
repeating 9's: 9 9 9 9
86 8
6
same number of 0's as 9's
in the square 0
0 0 0
a final 49
4 9
- So 999993 × 999993 = 999986000049.
|